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Grade 12th passElectric Current

hollow cylindrical conductor has a length 1 metre and inner and Outer radii 1 mm and 2 mm respectively .The resistivity of the material is 2 * 10^ 8 ohm metre . The resistance is?

Profile image of sohan goswami
8 Years agoGrade 12th pass
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2 Answers

Profile image of Khimraj
8 Years ago
the resistance is given by
dR = \rhodr/2\pirL
R = (\rho/2\piL)\int_{r}^{R}dr/r
R = (\rho/2\piL)ln(R/r)
Put values of L, \rho,R and r. You will get answer.
Profile image of harini
8 Years ago
resistance = resistivity ( length / area )
AREA of a hollow cylinder = ​\Pi (R2 - r2 ) = 3.14 x (4 – 1) x 10-6 = 9.42 x 10-6 m2
          resistivity = 2 x 10 -8  \Omega m     (** the resistivity provided in the question has an error)        
RESISTANCE = 2 x 10 -8  x 1 / 9.42 x 10 -6
                        = 2.1 x 10-3 \Omega

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