Niranjan Pandey of Cambridge
Last Activity: 5 Years ago
Let the resistivity of wire be p.
Let the length of wire be l.
Let the area of cross-section of wire be A.
Then the resistence of wire is given by R=p(l/A)
Assuming the wire to be cylindrical, the new length of wire br 10(l).
The voume of wire remains constant.
Let the new area of cross-section be A2.
Now,πr2h=volume of cylinder.
Also,πr2 =area
Thus area*length=volume.
A/q A*l=A2*(10 l)
A=10(A2)
A2=A/10
Thus new resistence R2= p(10l)/A2
R2=p(10l)/(A/10)
R2= p(100l)A
=100(pl/A)
Comparing it with original resistance R2 =100R i.e. 100 ohm