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Grade: 
        
Good afternoon sir.
Joules law application problem.
Explain it sir.
one year ago

Answers : (1)

View Solution
Arun
22533 Points 
							
Dear Raju
 
p’ = V’ ^2 / R
 
P’ = (110 / 2)^2 / R = 11 0 * 110 * P/ 2 * 2 * V^2
 
 = 110 * 110 * 320 / 2 * 2 * 220 *220
 
 = 20 Watts
 
 
 
Regards
Arun (askIITians forum expert)
one year ago
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