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Five capacitors are connected as shown in the figure. Initially S is opened and all capacitors are uncharged. When S is closed, steady state is obtained. Then find out potential difference between M and N

Five capacitors are connected as shown in the figure. Initially S is opened and all capacitors are uncharged. When S is closed, steady state is obtained. Then find out potential difference between M and N

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Grade:11

1 Answers

Khimraj
3007 Points
2 years ago
equivalent capacitance is ½ and EMF is 24
so charge through each capacitor = 12 \muC
So volatge across 4\muF is 3V and across 6\muF is 2V
So potential difference between M and N = 3 + 7+ 2 = 12V
HOpe it clears.
 

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