HI PATA VENKATESWARLU!
I WISH I COULD INSERT AN IMAGE,
THE QUESTION IS PREETY SIMPLE
DEVIDE THE CIRCUIT IN THREE EASY CIRCUITS TTHAT YOU SEE IN YOU ATTACHMENT CLEARLY : TOP,MIDDLE,BOTTOM
AS WE KNOW P IS NULL POINT 0 A CURRENT WILL FLOW THROUGH THE GALVANOMETER
ALSO THE LEFTMOST WIRE OF MIDDLE LOOP WON’T CARRY ANY CURRENT – AS ITS OBVIOUS
NOW FIND CURRENT IN TOP AND BOTTOM CIRCUITS SEPARATELY V=IR
IN TOP LOOP IT WILL BE 3 A
AND IN BOTTOM LOOP IT WIIL BE 5A
NOW SEE THE MIDDLE CIRCUIT AGAIN AND APPLY KVL IN IT YOU WILL GET THE FOLLOWING EQ.
3*(20/10)(10-X)+5 *2 = 20
THEREFORE X WILL BE 25/3
PLEASE APPROVE