Grade upto college level Electric Current

Find the time required for a 50 Hz alternating current to change its value form zero to the rms value.

Shane Macguire

12 Years agoGrade upto college level

3 Answers

Aditi Chauhan

12 Years ago

Sol. f = 50 Hz I = I base 0 Sin Wt Peak value I = I base 0/√2 I base 0/√2 = I base 0 Sin Wt ⇒ I base 0/√2 Sin Wt = Sin π/4 ⇒ π/4 = Wt. or, t = π/400 = π/4 * 2πf = 1/8f = 1/8 * 50 = 0.0025 s = 2.5 ms

Arun Kumar

12 Years ago

Hello

$\\v(t)=vsin(2\pi 50t) \\v_{rms}={ v \over \sqrt2} \\=>$so v(t)=0 at t=0$ \\=>v(t)={v \over \sqrt2} \\=>2\pi 50t={\pi \over 4} \\=>t={1 \over 100}$

Thanks & Regards
Arun Kumar
Btech, IIT Delhi
Askiitians Faculty

Kushagra Madhukar

5 Years ago

Dear student,

Please find the solution to your problem below.

Let the equation of alternating current be

V(t) = v sin (2πft) = v sin (2π50t) = v sin (100πt)

Now, v_rms = v/√2

Hence, v sin (100πt) = v/√2

or, sin (100πt) = 1/root2

or 100πt = π/4

or, t = 1/400 s = 2.5 x 10^-3 s = 2.5 ms

Hope it helps.

Thanks and regards,

Kushagra

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Find the time required for a 50 Hz alternating current to change its value form zero to the rms value.

Shane Macguire

3 Answers

Aditi Chauhan

Arun Kumar

Kushagra Madhukar

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