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`        Find the potential difference across a resistor of resistance 10 ohm, if 10 to the power 20 electrons flow through it in one second .`
one year ago

Utsav Basu
70 Points
```							1020 electron pass through the resistor in one second.
So, charge flowing through it = 1020 * 1.6 * 10-19 C = 16 C
Current = 16/1 A = 16 A
Now, using V = IR, we get,
Potential difference = 16 A * 10 Ω = 160 V
```
one year ago
Gitanjali Rout
184 Points
```							1020 electron pass through the resistor in one second.
So, charge flowing through it = 1020 * 1.6 * 10-19 C = 16 C
Current = 16/1 A = 16 A
Now, using V = IR, we get,
Potential difference = 16 A * 10 Ω = 160 V

```
one year ago
Gitanjali Rout
184 Points
```							So, charge flowing through it = 1020 * 1.6 * 10-19 C = 16 CCurrent = 16/1 A = 16 ANow, using V = IR, we get,Potential difference = 16 A * 10 Ω = 160 V
```
one year ago
Gitanjali Rout
184 Points
```
So, charge flowing through it = 1020 * 1.6 * 10-19 C = 16 C
Current = 16/1 A = 16 A
Now, using V = IR, we get,
Potential difference = 16 A * 10 Ω = 160 V.

```
one year ago
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### Course Features

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### Course Features

• 110 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions