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Find the equivalent resistance between X and Y of the network shown in the figure
Look from X.5 ohm and 10 ohm are in parallel.Their equivalent resistance =10/3 ohmNow erase the part AFE.replace the resistance 10 ohm between AB by 10/3 ohm.Now again look at ckt.current flowing from X through 10/3 ohm.at the point B it again breaks up in two component.(5+10)=15 ohm in parallel to 5 ohm.Equivalent resistance=15/4 ohm.So finally the ckt becomes 10/3 in series with 15/4.Or total equivalent resistance=85/12 ohm.
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