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Find the electric field strength due to a point charge of 5 micro coloum at a distance of 80 cm from the charge
As we knowE = V * rHenceE = (1/4* pi* epsilon) * (q/r)E = 9 * 10^9 *5 * 10^-6 /0.8E = 45000/0.8E = 56250 volt - m
Electric field due to a point charge is given byE = Kq/r2K = 9*109q = 5*10-6Cr = 0.8mSO E = 7.03*104 Vm.Hope it clears.
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