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Grade: 12
        
Find the electric field strength due to a point charge of 5 micro coloum at a distance of 80 cm from the charge
5 months ago

Answers : (2)

Arun
23048 Points
							
 
As we know
E = V * r
Hence
E = (1/4* pi* epsilon) * (q/r)
E = 9 * 10^9 *5 * 10^-6 /0.8
E = 45000/0.8
E = 56250 volt - m
5 months ago
Khimraj
3008 Points
							
 
Electric field due to a point charge is given by
E = Kq/r2
K = 9*109
q = 5*10-6C
r = 0.8m
SO 
E = 7.03*104 Vm.
Hope it clears.
4 months ago
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