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Electrons,each with charge e,move with speed v along a metal wire.the electric current in the wire is I.Plane P is perpendicular to the length of wire.How many electrons pass through plane P in each second?
Dear student,Charge passing the plane in each second=ITherefore, number of electrons passing the plane in each second=
Brother, Charge carriers are electrons The equation represents that, q=it and q=ne Thus, ne=it So,. n= it/e According the question time t=1 Hence, number of electrons passing through out the plane each second = I/e
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