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`        Electrons,each with charge e,move with speed v along a metal wire.the electric current in the wire is I.Plane P is perpendicular to the length of  wire.How many electrons pass through plane P in each second?`
one year ago

## Answers : (2)

Eshan
2095 Points
```							Dear student,Charge passing the plane in each second=ITherefore, number of electrons passing the plane in each second=$\dpi{80} \dfrac{I}{e}$
```
one year ago
yathartha gupta
71 Points
```							Brother,               Charge carriers are electrons        The equation represents that,                  q=it and q=ne              Thus, ne=it So,.        n= it/e              According the question time t=1        Hence,         number of electrons passing through out the plane each second = I/e
```
one year ago
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### Course Features

• 110 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions