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Electrons,each with charge e,move with speed v along a metal wire.the electric current in the wire is I.Plane P is perpendicular to the length of wire.How many electrons pass through plane P in each second?

Rizwan , 6 Years ago
Grade 12th pass
anser 2 Answers
Eshan

Last Activity: 6 Years ago

Dear student,

Charge passing the plane in each second=I
Therefore, number of electrons passing the plane in each second=\dfrac{I}{e}

yathartha gupta

Last Activity: 6 Years ago

Brother,
               Charge carriers are electrons  
      The equation represents that,
                  q=it and q=ne
              Thus, ne=it
 So,.        n= it/e
              According the question time t=1
        Hence,         number of electrons passing through out the plane each second = I/e

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