Navjyot Kalra
Last Activity: 11 Years ago
Sol. i = ne or n = i/e
‘e’ is same in all cases.
We know,
i = AST2 e^-∅/RT ∅ = 4.52 eV, K = 1.38 * 10^–23 J/k
n(1000) = As * (1000)^2 * e^-4.52*1.6*10^-19 /1.38*10^-23 *1000
⇒ 1.7396 * 10^-17
a)T = 300 K
n(T)/n(1000K) = AS*(300)^2 * e^-4.52*1.6*10^-19 /1.38*10^-23 *300/AS * 1.7396 * 10^-17 = 7.05 * 10^-55
b) T = 2000 K
n(T)/n(1000K) = AS*(2000)^2 * e^-4.52*1.6*10^-19 /1.38*10^-23 *2000/AS * 1.7396 * 10^-17 = 9.59 * 10^11
c) T = 3000 K
n(T)/n(1000K) = AS*(3000)^2 * e^-4.52*1.6*10^-19 /1.38*10^-23 *3000/AS * 1.7396 * 10^-17 = 1.340 * 10^16