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at what rate would it be necessary for a single conductor to cut the flux in order that a current of 1.2ma flows through it when 10 ohms resistor is connected. a) 1.2 * 10^-3 b) 1.2 * 10^-2 c) 1.3 * 10^-3 d) 1.1 * 10^-3
Dear student e = N d(phi)/dt e = IR d (phi)dt = e/N = 1.2 * 10^-2 wb Hope it helps RegardsArun (askIITians forum expert)
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