Deepak Patra
Last Activity: 11 Years ago
Sol. (a)For current to be maximum in a circuit
X base l = X base c (Resonant Condition)
⇒ WL = 1/WC
⇒W^2 = 1/LC = ½ * 18 *10^-6 = 10^6/36
⇒ W = 10^3/6 ⇒ 2πf = 10^3/6
⇒ f = 1000/6 * 2π = 26.537 Hz = 27 Hz
(b) Maximum Current = E/R (in resonance and)
= 20/10 * 10^3 = 2/10^3 A = 2 mA