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Grade: 12th pass

                        

An electric current of 5 hampered is divided into 3 branches along 3 wires of same material with same cross section but with their lengths in theproportion1:2:3 .then the current in the middle branch will be

2 years ago

Answers : (1)

Ehssas Samal
11 Points
							R is directly proportional to the length of the conductor. So R¹:R²:R³ = 1:2:3Let R¹ be = xSo,  R² = 2xAnd,  R³ = 3xNow,  R(eq.) = (R¹R²R³)/(R¹R² + R²R³ + R³R¹)                      = 6x/11Now,            I = V/R=>   5 = V/(6x/11) = 11x/6 * V=> V = 30x/11 Now I² = V/R             = 30x/11 * 1/2x = 15/11So,  the current flowing in the middle branch will be 15/11 A.
						
2 years ago
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