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Grade: 12
A storage battery of emf 12V and internal resistance 0.5 ohm, is to be charged by a 120V D.C supply of negligible internal resistance. What resistance is required in the circuit for the charging current to be 3A? 
i)How much chemical energy from the dc source is converted to electrical energy?
ii)How much electrical energy is converted to chemical energy in the storage battery?
3 months ago

Answers : (2)

23811 Points


By applying Kirchoff's voltage law , we get,   3R + 12 + (3×0.5) = 120 
From abov eqn., we get R = 35.5 Ω
If t is charging time in seconds, electrical energy converted into chemical energy in storage battery = ( 12 × 3 × t ) J = 36t J
If t is charging time in seconds, chemical energy converted into electrical energy in dc source = ( 120 × 3 × t ) J = 360t J
3 months ago
Vikas TU
10573 Points
Dear student 
The Resistance value is incorrect 
Applying Kirchoff voltage rule we get
net emf =     (120-12)=117 V , net resistance =( R+r)   and net current =3A
​now 117=i xRnet
117/3 =r+R
39-0.5 =R=38.5 Ω
Hope this will help 
3 months ago
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