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A small copper sphere carrying a charge of +0.9 microcolumb is placed at a distance separated by vacuum by 3m from an other identical sphere of charge-0.9 microcolumb in vacuum. They attract each other with a certain force. The new force between them when 5*10^12 electrons are removed from each sphere is?

Prajwal , 6 Years ago

Grade 12

1 Answers

Eshan

Last Activity: 6 Years ago

Dear student,

Initial charge on each of the spheres= $q_1=+0.9\mu C$ .

Final charge on first sphere when electrons are removed from them= $q_2=0.9\mu C+(1.6\times 10^{-19}C)(5\times 10^{12})=1.7\mu C$

Final charge on second sphere when electrons are remvod= $q_3=-0.9C+(1.6\times 10^{-19}C)(5\times 10^{12})=-0.2\mu C$

$\implies F_{new}=\dfrac{1}{4\pi\epsilon_0}\dfrac{q_2q_3}{d^2}=0.00034N$

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