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a piece of cloud having area 25*10^6 m^2 and electric potential of 10^5 volt. if the height of cloud is 0.75 km. then the energy density of electric field between earth and cloud will be:
(1) 1475 J (2) 1225 J (3) 750 J (4) 250 J

jayprakash pal , 7 Years ago
Grade 12
anser 1 Answers
Arun
Dear student
 
Use E = 1/2 × E°× (E)^2 × (A×d) = 1/2 × E°×(V/d)^2 × (A×d) E°= 8.85 × (10)^-12 V = (10)^5 A = 25×(10)^6 d = 0.75 × (10)^3 --> Answer = 1475 J
 
 
Regards
Arun (askIITiams forum expert)
Last Activity: 7 Years ago
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