Jitender Pal
Last Activity: 11 Years ago
Sol. E = 5 Kv/m = 5 * 10^3 v/m ; t = 1 μs = 1 * 10^–6 s
F = qE = 1.6 * 10^–9 * 5 * 10^3
A = qE/m = 1.6 *5 *10^-6/9.1 *10^-31
a) S = distance travelled
= 1/2 at^2 = 439.56 m = 440 m
b) d = 1 mm = 1 * 10^-3 m
1 * 10^-3 = 1/2 * 1.6 * 5/9.1 10^5 * t^2
⇒ t^2 = 9.1/0.8 * 5 * 10^-18 ⇒ t = 1.508 * 10^-9 sec ⇒ 1.5 ns.