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A loThe current density across a cylinder conductor of radius R
You have to use polar coordonate (r,).An elemental area dS=rdrd.Now elementary current is dI=J.dSWe have to integrate r from 0 to R, from 0 to 2 to obtain total current I. Please carry it out yourself. If you face problem then only ask me.The ans will be The next problem will be in the same manner with the value of J as given in it.
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