Thank you for registering.

One of our academic counsellors will contact you within 1 working day.

Please check your email for login details.
Close
MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

⇐ BackProceed to Checkout ⇒
There are no items in this cart.
Continue Shopping

A loThe current density across a cylinder conductor of radius R

A loThe current density across a cylinder conductor of radius R

Question Image
Grade:12th pass

1 Answers

Susmita
425 Points
2 years ago
You have to use polar coordonate (r,\theta).
An elemental area dS=rdrd\theta.
Now elementary current is  
dI=J.dS
We have to integrate r from 0 to R,\theta from 0 to 2\pi to obtain total current I.
\int_{0}^{R} Jo (1-\frac{r}{R})rdr\int_{0}^{2\pi}d\theta
 Please carry it out yourself. If you face problem then only ask me.
The ans will be (\pi Jo R^2)/3
The next problem will be in the same manner with the value of J as given in it.

Think You Can Provide A Better Answer ?

Provide a better Answer & Earn Cool Goodies See our forum point policy

Other Related Questions on Electric Current

View all Questions »

ASK QUESTION

Get your questions answered by the expert for free

Register ICAT

Answer and earn gift vouchers

Win Gift vouchers upto Rs 500/-

View courses by askIITians

Design classes One-on-One in your own way with Top IITians/Medical Professionals

Click Here Know More

Complete Self Study Package designed by Industry Leading Experts

Click Here Know More

Live 1-1 coding classes to unleash the Creator in your Child

Click Here Know More

a Complete All-in-One Study package Fully Loaded inside a Tablet!

Click Here Know More