Grade 12th passElectric Current

A loThe current density across a cylinder conductor of radius R

Kaddsy

7 Years agoGrade 12th pass

7 Years ago

You have to use polar coordonate (r, $\theta$ ).

An elemental area dS=rdrd $\theta$ .

Now elementary current is

dI=J.dS

We have to integrate r from 0 to R, $\theta$ from 0 to 2 $\pi$ to obtain total current I.

$\int_{0}^{R} Jo (1-\frac{r}{R})rdr\int_{0}^{2\pi}d\theta$

Please carry it out yourself. If you face problem then only ask me.

The ans will be $(\pi Jo R^2)/3$

The next problem will be in the same manner with the value of J as given in it.

electric current

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electric current

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electric current

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electric current

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electric current

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