A dry cell of emf 1.6V and internal resistance 0.1ohm is connected to a resistor of R Ohms. if 2A current is flowing in the circuit, calculate the voltage drop across R

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utpal raj · Answer

hiii anusha total resistance in the circuit = R+0.1=R1 according to ohms law V=IR1 1.6=2*R1 R1=0.8 ohm 0.8 = 0.1+R R=0.7 ohm voltage across R = 0.7*2=1.4 volt , the current passing through R is 2 amp so , hope this clears please aproove good luck

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A dry cell of emf 1.6V and internal resistance 0.1ohm is connected to a resistor of R Ohms. if 2A current is flowing in the circuit, calculate the voltage drop across R

A dry cell of emf 1.6V and internal resistance 0.1ohm is connected to a resistor of R Ohms. if 2A current is flowing in the circuit, calculate the voltage drop across R

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