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# A cell of emf E is connected across a resistance R. The potential difference across the terminals of the cell isfound to be V volt. Internal resistance of cell isa] (E-V)Rb] (E-V)R/Vc] 2(E-V)R/Ed] 2(E-V)V/R

24 Points
3 years ago
Assume a circuit (with the given conditions) :
Emf(E) , Internal Resistance(r), External Resistance(R)
When no current is drawn from the cell :
Emf(E) = Internal Potential Difference(V”) //across the plates of the emf.
But, when current(i) is drawn :
Emf(E) = V” + V //due to potential drop, external potential difference is obtained (V) ; as mentioned.
Now, since : V” = i . r ;
Then, E = V” + V will become,
>  E = (i . r) + V
>  E – V = i . r
>  (E – V) / i = r
since, i = V / R ;
>  (E – V) / (V / R) = r
>  {(E – V) . R} / V = r  //ans(b)
ankit singh