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Grade: 12
        A cell develops the same power across 2 resistance R1 and R2 separately the internal resistance of the cell is
11 months ago

Answers : (1)

Arun
16089 Points
							
Dear Student
Let r be the internal resistance of the cell and E its EMF. When connected across the resistance R1 in the circuit, current passing through the resistance is

i = E/R1 + r

So, P1 = i2R1 = [E/(R1+r)]2R1

Similarly P2 = [E/(R2 +r)]2 R2

Given that P1 = P2

Substituting the values, we get,

r = √(R1R2)

Regards

Arun (askIITians forum expert)

11 months ago
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