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a battery of emf 15V and internal resistant 3ohm is connected to two resistors 3ohm and 6 ohm connected in parallel find p.d. between the terminals of the battery
HI Reema,total resistance R = 3 + (3*6)/(3+6) = 5 ohmemf = 15V current though terminal of battery i = V/R = 15/5 =3A p.d. between terminals = emf – i*(internal resistance) = 15 – 3*3 =15 – 9 = 6VApprove if you are satisfied :)
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