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`        A 9 V battery is connected in series with a resistor .The terminal voltage is found to be 8 V.Current through the circuit is measured as 5 A. What is the internal resistance of the battery?`
one year ago

Arun
23521 Points
```							As we know battery supplied voltage = E - IrWhere E is the EMF of cell , I is the current passing through battery and r is internal resistance of battery . Putting all the values we get8=9-5×r=> r=1/5 =0.2 ohm
```
one year ago
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### Course Features

• 110 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions