) A 12 kW heater having efficiency 80% is connected to a 220 V, 50 Hz supply. Find the reactive component of the input current if its power factor is 0.75 lagging.

Question

Vikas TU · Answer

Power actual = 0.8 * 12 => 9.6 KW = > 9600 Watt. 9600 = Irms x 220/root2 x 0.75 Irms = 82.2690 A. the reactive current and resistance current would be same as in series .

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) A 12 kW heater having efficiency 80% is connected to a 220 V, 50 Hz supply. Find the reactive component of the input current if its power factor is 0.75 lagging.

)
A 12 kW heater having efficiency 80% is connected to a 220 V, 50 Hz supply. Find the reactive component of the input current if its power factor is 0.75 lagging.

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) A 12 kW heater having efficiency 80% is connected to a 220 V, 50 Hz supply. Find the reactive component of the input current if its power factor is 0.75 lagging.

)A 12 kW heater having efficiency 80% is connected to a 220 V, 50 Hz supply. Find the reactive component of the input current if its power factor is 0.75 lagging.

1 Answers

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A 12 kW heater having efficiency 80% is connected to a 220 V, 50 Hz supply. Find the reactive component of the input current if its power factor is 0.75 lagging.