20 g of a binary electrolyte (mol.wt. = 100) are dissolved in 500 g of water. The freezing point of the solution is –0.74°C, Kf = 1.86 K.molality–1. The degree of ionisation of the electrolyte is

Question

Arun · Answer

Delta T = 1000 *Kf * w/m* 500 0.74 = 1000* 1.86* 20/m*500 on solving m = 100 Actual molar mass = 100 Hencce degree of ionisation = 0%

Rishi Sharma · Answer

Dear Student,
Please find below the solution to your problem.

Delta T = 1000 *Kf * w/m* 500
0.74 = 1000* 1.86* 20/m*500
on solving
m = 100
Actual molar mass = 100
Hencce degree of ionisation = 0%

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20 g of a binary electrolyte (mol.wt. = 100) are dissolved in 500 g of water. The freezing point of the solution is –0.74°C, Kf = 1.86 K.molality–1. The degree of ionisation of the electrolyte is

20 g of a binary electrolyte (mol.wt. = 100) are dissolved in 500 g of water. The freezing point of the solution is –0.74°C, Kf = 1.86 K.molality–1. The degree of ionisation of the electrolyte is

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20 g of a binary electrolyte (mol.wt. = 100) are dissolved in 500 g of water. The freezing point of the solution is –0.74°C, Kf = 1.86 K.molality–1. The degree of ionisation of the electrolyte is

20 g of a binary electrolyte (mol.wt. = 100) are dissolved in 500 g of water. The freezing point of the solution is –0.74°C, Kf = 1.86 K.molality–1. The degree of ionisation of the electrolyte is

2 Answers

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