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20 g of a binary electrolyte (mol.wt. = 100) are dissolved in 500 g of water. The freezing point of the solution is –0.74°C, Kf = 1.86 K.molality–1. The degree of ionisation of the electrolyte is
Delta T = 1000 *Kf * w/m* 5000.74 = 1000* 1.86* 20/m*500on solvingm = 100Actual molar mass = 100Hencce degree of ionisation = 0%
Dear Student,Please find below the solution to your problem.Delta T = 1000 *Kf * w/m* 5000.74 = 1000* 1.86* 20/m*500on solvingm = 100Actual molar mass = 100Hencce degree of ionisation = 0%Thanks and Regards
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