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Grade: 12th pass
        
2 parallel plates of a capacitor having area 200cm^2 are given equal and opposite charges of magnitude 1.78micro Coulomb. Electric field in the dielectric is1.5*10^6 V/m.what's the magnitude of charge induced in the dielectric?
9 months ago

Answers : (1)

Yash Patil
33 Points
							
C=EoA/d
E=Vd --------- Q=CV=EoAV/d=EoAE
 
Find Q by puttin values of area and field.
Subtract from the given value of Q=1.78mc
8 months ago
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