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The emf of the driver cell of a potentiometer is 2V & its internal resistance is negligible . The length of the potentiometer wire is 100cm & resistance is 5 ohm.How much resistance is to be connected in series with the potentiometer wire to have a potential gradient of 0.05V/cm?

The emf of the driver cell of a potentiometer is 2V & its internal resistance is negligible . The length of the potentiometer wire is 100cm & resistance is 5 ohm.How much resistance is to be connected in series with the potentiometer wire to have a potential gradient of 0.05V/cm?

Grade:11

5 Answers

Arjun Shamsunder
31 Points
8 years ago

Potential gradient K= 0.05 V/cm = 5V/m
Driver cell emf E=2V
Resistance of potentiometer wire R1= 5Ω/m
Series resistance, Rs= ?

Now, to have K=5V/m, current flowing through the wire must be 1 Ampere (  since current I= 5V/5Ω=1A)
So, for the driver cell of emf 2V to generate 1A of current, series resistance ro be connected is 2Ω( since Rs= E/I=2/1=2Ω)

Therefore, Rs=2Ω

Anubhav Sharma
5 Points
8 years ago

the resistance connected to be in series wih wire should be 7.5 ohm

is it right 

Anubhav Sharma
5 Points
8 years ago

the resistance to be connected should be 7.5 ohm 

is it right

Ranjita yadav
35 Points
8 years ago

The ans is 1995ohm.

Arjun Shamsunder
31 Points
8 years ago

I think its a wrong question

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