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A town situated 20km away from a power plant generating power at 440V , requires 600 Kw of electric power at 200 V . The resistance of two line wires carrying power is 0.4 ohm per km . the towns gets power from line through 3000-220 V step up transformer at a substation in the town
1) find the power losses in the form of heat?
2) how much power must the plant supply assuming there is a negligible power loss due to leakage ?
3) what is the voltage drop on the line ?
ans : 1) 640 KW
2) 1240 kW
3) 3200V
Answer :
Total resistance 0.4*40 = 16Ω
Irms on line = Power / Volt = ( 600 * 1000 ) / 3000 = 200 A
Line power loss = (Irms)2 * R = (200)2 * 16 = 640000 W = 640 KW
Power suplied = 600 + 640 = 1240 KW
Voltage drop = Irms * R = 200 * 16 = 3200 V
................. THANK YOU ......................
to all who didnt posted any reply to this so far as that made me to find a solution to this myself :)
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