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Two heating coils A and B made of the same material are connected in parallel across yhe mains.The length and diameter of A are twice those of B.In which will more heat be produced and by how much?
RB =(ρl)/(∏(x/2)2) let x be the diameter of the coil B
RB = (4ρl)/(∏x2)
RA = (ρ2l)/(∏x2)
on comparing the resistance of these two we will get
2RA = RB
applying the formula P= V2/R
since the value of RA is smaller than RB then the heat energy will be more in the A coil.
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