a parallel plate capacitor of area a and seperation d is supplied a potential diff p.the battery is disconnected and dielecric of thickness t

Dear Charitha,

For a Parallel plate capacitor,

A= Area 

d=Thickness (d)

also Q= C. V

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if dielectric of thickness 't' is introduced, the configuration is equivalent to two capacitors in series: one capacitor has capacitance C1=(ε₀a)/(d-t) and C2=(ε₀ka)/t, where k is the dielectric constant. The equivalent capacitance of the combination is (C1*C2)/(C1 +C2)