a parallel plate capacitor of area a and seperation d is supplied a potential diff p.the battery is disconnected and dielecric of thickness t the E IN THE GAPS OF PLATE AND DIELECTRIC?
E IN THE DIELECRIC SLAB?????/

Question

Aman Bansal · Answer

Dear Charitha,

For a Parallel plate capacitor,

A= Area

d=Thickness (d)

also Q= C. V

Best Of luck

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Chetan Mandayam Nayakar · Answer

if dielectric of thickness 't' is introduced, the configuration is equivalent to two capacitors in series: one capacitor has capacitance C1=(&epsilon; 0 a)/(d-t) and C2=(&epsilon; 0 ka)/t, where k is the dielectric constant. The equivalent capacitance of the combination is (C1*C2)/(C1 +C2)

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a parallel plate capacitor of area a and seperation d is supplied a potential diff p.the battery is disconnected and dielecric of thickness t the E IN THE GAPS OF PLATE AND DIELECTRIC? E IN THE DIELECRIC SLAB?????/

a parallel plate capacitor of area a and seperation d is supplied a potential diff p.the battery is disconnected and dielecric of thickness t the E IN THE GAPS OF PLATE AND DIELECTRIC?
E IN THE DIELECRIC SLAB?????/

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a parallel plate capacitor of area a and seperation d is supplied a potential diff p.the battery is disconnected and dielecric of thickness t the E IN THE GAPS OF PLATE AND DIELECTRIC? E IN THE DIELECRIC SLAB?????/

a parallel plate capacitor of area a and seperation d is supplied a potential diff p.the battery is disconnected and dielecric of thickness t the E IN THE GAPS OF PLATE AND DIELECTRIC? E IN THE DIELECRIC SLAB?????/

2 Answers

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a parallel plate capacitor of area a and seperation d is supplied a potential diff p.the battery is disconnected and dielecric of thickness t the E IN THE GAPS OF PLATE AND DIELECTRIC?
E IN THE DIELECRIC SLAB?????/