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An electrical circuit is shown in the figure. Show that the p.d across the resistor of 400 ohmas will be measured by the voltmeter V of resistance 400 ohm is 20/3 V.
since voltmeter resisitance is 400 ohms Rab = 400*400/800 = 200 ohms , Rad = 100 , Rcd= 100 ,Rbc =200 and Rac =100 ohms as Rab/Rbc = Rad/Rcd , by wheat stone bridge priciple, no current flows through Rac, so it can be removed from circuit now, to fin volatge across, V , let I be current in circuit, the on simplyfying resistance Rbd = 150 ohms hence, I = 1/15 A current in voltmeter = I/2 = 1/30 A voltage across it = 1/30 * 200 = 20/3 V -- Please feel free to post as many doubts on our disucssion forum as you can. If you find any question difficult to understand - post it here and we will get you the answer and detailed solution very quickly.We are all IITians and here to help you in your IIT JEE preparation. All the best.Regards,Ramesh IIT Kgp - 05 batch
since voltmeter resisitance is 400 ohms
Rab = 400*400/800 = 200 ohms , Rad = 100 , Rcd= 100 ,Rbc =200 and Rac =100 ohms
as Rab/Rbc = Rad/Rcd , by wheat stone bridge priciple, no current flows through Rac, so it can be removed from circuit
now, to fin volatge across, V , let I be current in circuit,
the on simplyfying resistance Rbd = 150 ohms
hence, I = 1/15 A
current in voltmeter = I/2 = 1/30 A
voltage across it = 1/30 * 200 = 20/3 V
--
Please feel free to post as many doubts on our disucssion forum as you can. If you find any question difficult to understand - post it here and we will get you the answer and detailed solution very quickly.We are all IITians and here to help you in your IIT JEE preparation. All the best.Regards,Ramesh IIT Kgp - 05 batch
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