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a potential differance is applied btw the plates of parallel plate capacitor of area Aand seperation d,.the battery is disconnected and a dielactric of constant K is placed btw plates of capacitor of thickness t now why the electric field in the gaps of dielectric isv/d instead ofv/d-t and Ein dielectric is v/kd and nt v/kt

a potential differance is applied btw the plates of parallel plate capacitor of area Aand seperation d,.the battery is disconnected and a dielactric of constant K is placed btw plates of capacitor of thickness t now why the electric field in the gaps of dielectric isv/d instead ofv/d-t and Ein dielectric is v/kd and nt v/kt

Grade:11

1 Answers

SAGAR SINGH - IIT DELHI
878 Points
12 years ago

Dear charitha,

C= K*Eo*A/D, where  Eo= 8.854x10-12

where:

K is the dielectric constant of the material,
A is the overlapping surface area of the plates,
d is the distance between the plates, and
C is capacitance

A (plate area) (mm2)
d (distance) (mm)
K (dielectric constant )

Capacitance (uF)
Capacitance (pF)

 

 

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