Ques1) Two square metal plates A and B are of the same thickness and material. The side of B is twice of that A. These are connected in series. Let the resistances of A and B are denoted by R A and R B. Then show that R A / R B =1.

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himanshu dev sharma · Answer

Ramesh V · Answer

R = pL/A R 1 = pL/L*t and R 2 = p(2L)/2L*t = pL/L*t which gives : R 1 / R 2 = 1 -- Please feel free to post as many doubts on our disucssion forum as you can. If you find any question difficult to understand - post it here and we will get you the answer and detailed solution very quickly. We are all IITians and here to help you in your IIT JEE preparation. All the best. Regards, Naga Ramesh IIT Kgp - 2005 batch

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Ques1) Two square metal plates A and B are of the same thickness and material. The side of B is twice of that A. These are connected in series. Let the resistances of A and B are denoted by R A and R B. Then show that R A / R B =1.

Ques1) Two square metal plates A and B are of the same thickness and material. The side of B is twice of that A. These are connected in series. Let the resistances of A and B are denoted by R_A and R_B.Then show that R_A / R_B =1.

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Ques1) Two square metal plates A and B are of the same thickness and material. The side of B is twice of that A. These are connected in series. Let the resistances of A and B are denoted by R A and R B. Then show that R A / R B =1.

Ques1) Two square metal plates A and B are of the same thickness and material. The side of B is twice of that A. These are connected in series. Let the resistances of A and B are denoted by RA and RB. Then show that RA / RB =1.

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Ques1) Two square metal plates A and B are of the same thickness and material. The side of B is twice of that A. These are connected in series. Let the resistances of A and B are denoted by R_A and R_B.Then show that R_A / R_B =1.