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Sir please tell what is the phase angle between current and voltage when it pass through pure capacitance 1)60 2)90 3)180 4)0 and also tell how to find it through capacitance
E = Eosinwt ..............................1 Eo is the peak voltage E across capacitor = dq/c dq/c = Eosinwt differentiating this equation (1/c)(dq/dt) = Eowcoswt I = Eowc coswt ...................2 I = Eo/(1/wc) {coswt} 1/wc = Rc (capacitive reactance) I = Eowc {sin(pi/2 +wt)} .............3 [cos@ = sin(pi/2+@) ] comparing eq 1 & 3 we see that current leads the voltage by an angle of pi/2 therefore phase difference bw current & voltage across capacitor is 90o ....... approve if u like my ans
E = Eosinwt ..............................1
Eo is the peak voltage
E across capacitor = dq/c
dq/c = Eosinwt
differentiating this equation
(1/c)(dq/dt) = Eowcoswt
I = Eowc coswt ...................2
I = Eo/(1/wc) {coswt}
1/wc = Rc (capacitive reactance)
I = Eowc {sin(pi/2 +wt)} .............3 [cos@ = sin(pi/2+@) ]
comparing eq 1 & 3 we see that current leads the voltage by an angle of pi/2
therefore phase difference bw current & voltage across capacitor is 90o .......
approve if u like my ans
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