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if two bulbs of resistances R1 and R2 are conncted in series (with R1>R2) .this is conncted across a battery of p.d V. then

across which bulb greater power is dessipated. which hich bulb will grow brighter ? plzzzz explain...........

iit jee , 14 Years ago
Grade Upto college level
anser 1 Answers
Vinay Arya

Last Activity: 14 Years ago

Req=R1+R2

I=V/R1+R2

P=I2R

R1>R2

P1>P2

So the bulb with resistance R2 will grow brighter as less power is dissipited and the resistance is low.

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