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if 10^9 electrons move out of a body to another body every second,How much time is required to get a total charge of 1C of the other body?(ans=198 yers)

if 10^9 electrons move out of a body to another body every second,How much time is required to get a total charge of 1C of the other body?(ans=198 yers)

Grade:Upto college level

4 Answers

suryakanth AskiitiansExpert-IITB
105 Points
14 years ago

Dear anil,

we know that 1 Coulomb = 6.242×1018 eletrons

given 10^9 electrons take 1 secs

=> 10^9 electrons ------> 1 sec

=> 1 electrons ---------> 1/(10^9) secs

=> 6.242×1018 ------> 6.242×1018/ (10^9)

= 6.242×109 secs = 6.242×109/ (60*60*24*365)  years

=197.93 years

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6.242×1018

Naveen Kumar
17 Points
7 years ago
Dear Naveenwe know that 1 Coulomb = 6.242×1018 eletronsgiven 10^9 electrons take 1 secs=> 10^9 electrons ------> 1 sec=> 1 electrons ---------> 1/(10^9) secs=> 6.242×1018 ------> 6.242×1018/ (10^9)= 6.242×109 secs = 6.242×109/ (60*60*24*365) years=197.93 years
Chander pratap singh
19 Points
6 years ago
Bro it`s so simpleWe know 1 coloumb is =6.242×10^18 electrons10^9 electrons takes 1 second 1 electron takes 1/10^9 seconds6.24×10^18 electrons will take 6.24×10^18/10^9Which is equal to 6.24×10^9We have to calculate time so we will divide it from (60×60×24×365)Which is equal to 31536000When u will divide 6.24×10^9/31536000It will be equal to 197.8 years Or approximately 198 years
Rishi Sharma
askIITians Faculty 646 Points
4 years ago
Dear Student,
Please find below the solution to your problem.

we know that 1 Coulomb = 6.242×10^18 eletrons
given 10^9 electrons take 1 secs
=> 10^9 electrons ------> 1 sec
=> 1 electrons ---------> 1/(10^9) secs
=> 6.242×10^18 ------> 6.242×10^18/ (10^9)
= 6.242×109 secs = 6.242×10^9/ (60*60*24*365) years
=197.93 years
= 198 years (approx)

Thanks and Regards

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