12 cells, each of EMF 1.5 volt and internal resist

Question

12 cells, each of EMF 1.5 volt and internal resistance of 1.5 ohm are arranged in M rows each containing n cells connected in series such that this combination would send Maximum current through an external resistance of 0.5 ohm when m and n are:1)m=3,n=42)m=6,n=23)m=4,n=34)m=2,n=6

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If n cells are associated in lines, at that point the aggregate resistance will be (R1) = n*r where r is the inside resistance of every cell. For m lines, at that point the aggregate resistance will be  1/R = 1/R1+1/R1+… … .m = m/R1 As R1 = n*r 1/R = m/(n*r) R= (n*r)/m Current and power will be most extreme when the inward resistance is equivalent to the outside resistance (n*r)/m = 1.5 (n*0.5)/m = 1.5 n/m = 3 n=3m mn = 12 3m^2 = 12 m^2 = 4 m=2 and n=6

Electric Current> 12 cells, each of EMF 1.5 volt and intern...

12 cells, each of EMF 1.5 volt and internal resistance of 1.5 ohm are arranged in M rows each containing n cells connected in series such that this combination would send Maximum current through an external resistance of 0.5 ohm when m and n are:1)m=3,n=42)m=6,n=23)m=4,n=34)m=2,n=6

Lakshay Bhati , 7 Years ago

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Electric Current> 12 cells, each of EMF 1.5 volt and intern...

12 cells, each of EMF 1.5 volt and internal resistance of 1.5 ohm are arranged in M rows each containing n cells connected in series such that this combination would send Maximum current through an external resistance of 0.5 ohm when m and n are:1)m=3,n=42)m=6,n=23)m=4,n=34)m=2,n=6

Lakshay Bhati , 7 Years ago

Vikas TU

Provide a better Answer & Earn Cool Goodies

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