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Grade 12th passElectric Current

12 cells, each of EMF 1.5 volt and internal resistance of 1.5 ohm are arranged in M rows each containing n cells connected in series such that this combination would send Maximum current through an external resistance of 0.5 ohm when m and n are:1)m=3,n=42)m=6,n=23)m=4,n=34)m=2,n=6

Lakshay Bhati

9 Years agoGrade 12th pass

1 Answer

Vikas TU

Approved Tutor Answer9 Years ago

If n cells are associated in lines, at that point the aggregate resistance will be (R1) = n*r where r is the inside resistance of every cell.

For m lines, at that point the aggregate resistance will be

 1/R = 1/R1+1/R1+… … .m

= m/R1

As R1 = n*r

1/R = m/(n*r)

R= (n*r)/m

Current and power will be most extreme when the inward resistance is equivalent to the outside resistance

(n*r)/m = 1.5

(n*0.5)/m = 1.5

n/m = 3

n=3m

mn = 12

3m^2 = 12

m^2 = 4

m=2 and n=6

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