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Grade: 11
        
What mass of pure CaCO3 react completely with 100 cm cube of 0.1M Hcl solution
one year ago

Answers : (1)

Vikas TU
9484 Points
							
No. of moles = Molrity * Volume 
No. of mles of HCL = 100* 0.1 = 10 moles 
From the  balanced equation it can be seen that:
 2 moles of  react with 1 mole of 
Thus 10 moles of  react, 
The mass of  required to react completely with 100 mL of 0.1 M HCl is 3.8 grams.
 
3 months ago
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