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Grade:
        
Value of √i please explain step by step plzzzzzzzzzzzzzzzzzzzzzzzzz
 
3 months ago

Answers : (3)

Vikas TU
9499 Points
							
i = Cosπ/2 +i Sinπ/2 
-i = Cos (-π/2) + i Sin(-π/2) 
-i = e^ -iπ/2 
sqrt(-i) = + or - (Cos(-π/4) + i Sin(-π/4)
= (1-i)/sqrt(2)  
3 months ago
Aditya Gupta
1717 Points
							
note that i= e^i(pi/2)
now root i= i^(1/2)
= [e^i(pi/2)]^(1/2)
use de moivres theorem
= e^i(pi/4) or e^i(pi/4 + pi)
= (1+i)/root2 or – (1+i)/root2 
kindly approve :=)
3 months ago
Arun
23020 Points
							
√ ( √ -1 ) 

= √ ( √ -1 ) 

= ⁴√ -1 

= (⁴√ -1 )
 
hope it helps
In case of any difficulty, please feel free to qsk again
 
Regards
Arun
3 months ago
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