0

Guest

Courses New

The ratio of electrostatic potential at the centre of the cube to that at one of the corners of cube is

The ratio of electrostatic potential at the centre of the cube to that at one of the corners of cube is

Grade:12th pass

1 Answers

Arun
25750 Points
6 years ago
The charge density within the cube is ,say, d. Then, to find the potential at any point of the cube we have to solve the Poission’s equation ( Laplacian operator)V=-d/(epsilon zero). In the absence of boundary conditions it would be impossible to find the solutions of above mentioned Poissions equation.
If we don't want to solve Poissions equation then we have to evaluate the following volume integral over the volume of the cube.
V(r)=(1/4 pi eo) integral[d/(|r-r’|) (d tau), where eo is permittivity of space and d tau is volume element.
But, if the cube is conductor, all the charge will reside on the surface and field inside the cube will be zero. In this case , potential at the corner and at center will be same and the ratio asked for is 1.

Regards
Arun (askIITians forum expert)

Think You Can Provide A Better Answer ?

Other Related Questions on Discuss with colleagues and IITians

View all Questions »

ASK QUESTION

Get your questions answered by the expert for free

Answer and earn gift vouchers

Win Gift vouchers upto Rs 500/-

View courses by askIITians

Design classes One-on-One in your own way with Top IITians/Medical Professionals

Click Here Know More

Complete Self Study Package designed by Industry Leading Experts

Click Here Know More

Live 1-1 coding classes to unleash the Creator in your Child

Click Here Know More

a Complete All-in-One Study package Fully Loaded inside a Tablet!

Click Here Know More