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Grade: 12
        
Solve:        
Log 3/4log 8 (x2+7) +log1/2 log1/4(x2 +7)-1 =-2
3 years ago

Answers : (1)

Sumit Majumdar
IIT Delhi
askIITians Faculty
137 Points
							
Dear student,
Please confirm if the question is:
\left [ log_{3/4}log_{8} \right \left ( x^{2}+7 \right )]+\left [ log_{1/2}log_{1/4} \right \left ( x^{2}+7 \right )^{-1}]=-2
Then you can simplifiy this as follows:
\left [ log_{3/4}\left ( \frac{log\left ( x^{2}+7 \right )}{3log2} \right ) \right ]+\left [ log_{1/2}\left ( \frac{log\left ( x^{2}+7 \right )}{2log2} \right ) \right ]=-2
If we assume:
u=\frac{log\left ( x^{2}+7 \right )}{log2}
Then the bove expression can be solved easily.
Regards
Sumit
3 years ago
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