sin^2x – cos^2x – 1 assumes the least value for set of given values of x given by a. x= npie +(-1)^n+1(pie/6) x=npie+(-1)^n(pie/6) x+npie+9-1)^n(pie/3) x=npie-(-1)^n(pie/6)

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Arun Kumar · Answer

I'm removing -1 because it doesn't matter but here this is not the answer we have to chose from the options which gives the least value A,B,D Arun Kumar IIT Delhi Askiitians Faculty

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sin^2x – cos^2x – 1 assumes the least value for set of given values of x given by a. x= npie +(-1)^n+1(pie/6) x=npie+(-1)^n(pie/6) x+npie+9-1)^n(pie/3) x=npie-(-1)^n(pie/6)

sin^2x – cos^2x – 1 assumes the least value for set of given values of x given by
a. x= npie +(-1)^n+1(pie/6)
x=npie+(-1)^n(pie/6)
x+npie+9-1)^n(pie/3)
x=npie-(-1)^n(pie/6)

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sin^2x – cos^2x – 1 assumes the least value for set of given values of x given by a. x= npie +(-1)^n+1(pie/6) x=npie+(-1)^n(pie/6) x+npie+9-1)^n(pie/3) x=npie-(-1)^n(pie/6)

sin^2x – cos^2x – 1 assumes the least value for set of given values of x given bya. x= npie +(-1)^n+1(pie/6) x=npie+(-1)^n(pie/6)x+npie+9-1)^n(pie/3)x=npie-(-1)^n(pie/6)

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sin^2x – cos^2x – 1 assumes the least value for set of given values of x given by
a. x= npie +(-1)^n+1(pie/6)
x=npie+(-1)^n(pie/6)
x+npie+9-1)^n(pie/3)
x=npie-(-1)^n(pie/6)