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molal depression of freezing point of water is 1.86 per 1000g of water 0.02 mol of urea dissolved in 100g of water will produce a lowering of temperature of
Dear student Del Tf = (1000*Kf * w)/ (m*w)Del Tf = ( 1000* 1.86 * 342 )/(1000*342)=> 1.86 Tf = 0- 1.86 = -1.86 Hope this helps Cheers Good luck
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