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`        Log 2454 = a  and  log 12 18 = b .Then the value of [ab-5(a-b)] =`
5 years ago

Arun Kumar
IIT Delhi
256 Points
```							Hello Student,$\\a=log_{24}54={ln54 \over ln24}={ln3+ln18 \over ln2+ln12} \\a={3ln3+ln2 \over 3ln2+ln3}={3x+y \over 3y+x} \\b=log_{12}18={ln18 \over ln12} \\={2ln3+ln2 \over 2ln2+ln3}={2x+y \over 2y+x} \\=>ab-5(a-b) \\=>{3x+y \over 3y+x}*{2x+y \over 2y+x}-5({3x+y \over 3y+x}-{2x+y \over 2y+x}) \\=>{y^2+5xy+6x^2-5((3x^2+2y^2+7xy)-(3y^2+2x^2+7xy)) \over (2y+x)*(3y+x)} \\=>{y^2+5xy+6x^2 - 5(x^2-y^2) \over (2y+x)*(3y+x)}$$\\=>{6y^2+5xy+x^2 \over 6y^2+x^2+5xy} \\=>1$Thanks & RegardsArun KumarBtech, IIT DelhiAskiitians Faculty
```
5 years ago
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• 731 Video Lectures
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• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions