If the two numbers differ by 6, then their produce is given by the square of their average minus 9.

eg: 22*28= 25^2 - 9 = 616

Question

If the two numbers differ by 6, then their produce is given by the square of their average minus 9. eg: 22*28= 25^2 - 9 = 616

Saurabh Singh · Answer

x-y=6 x*y=(x+y)^2 -9 we can solve these two equations to get the desired numbers The solution can be plotted as Thanks & Regards Saurabh Singh, askIITians Faculty B.Tech. IIT Kanpur

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If the two numbers differ by 6, then their produce is given by the square of their average minus 9. eg: 22*28= 25^2 - 9 = 616

If the two numbers differ by 6, then their produce is given by the square of their average minus 9.

eg: 22*28= 25^2 - 9 = 616

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If the two numbers differ by 6, then their produce is given by the square of their average minus 9. eg: 22*28= 25^2 - 9 = 616

If the two numbers differ by 6, then their produce is given by the square of their average minus 9.eg: 22*28= 25^2 - 9 = 616

1 Answers

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If the two numbers differ by 6, then their produce is given by the square of their average minus 9.

eg: 22*28= 25^2 - 9 = 616