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Grade: 12th pass
        
How to solve greatest common divisor ( g.c.d. )of 1125 any 574
4 months ago

Answers : (4)

Aditya Gupta
2048 Points
							
We first perform the prime factorisation:
1125= 5^3*3^2
and 574= 2*7*41
Clearly there are no common prime factors. Hence the HCF or greatest common divisor (gcd) is equal to 1.
KINDLY APPROVE :))
4 months ago
Vikas TU
11761 Points
							
https://www.askiitians.com/revision-notes/class-6-maths/playing-with-numbers/Dear studentTo understand the processPlease find the link below
Good Luck 
4 months ago
Arun
24740 Points
							
Dear student
 
1125 = 3 * 3 * 5 *5 *5
574 = 2* 7 * 41
 
Hence HCF = G CD = 1 ( as nothing is common)
 
Hope is helpful
4 months ago
Yashraj
322 Points
							
i will again say just go through it once again 
the concept is to factorise them and then take common part that is gcd
3 months ago
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  • Study Planner
  • NCERT Solutions
  • Discussion Forum
  • Previous Year Exam Questions


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