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`        Explain plz Answer is ABTwo bodies A and B of masses 5 and 10 kg respectively moving in opposite direction with velocity is 4 and 0.5 make head on collision in free space the force of their mutual attraction during their collision and varies according to graph answer is ABExplain`
2 years ago

Shubham Kumar Gupta Ggps
42 Points
```							Use impulse momentum eqn: integral(F.dt)=final momentum - initial momentum. integral(F.dt) is the area under the curve= area of the triangle find the final velocities of the masses.let initial velocities of the 2 masses be u1 and u2 and final velocities be v1 and v2. coefficient of restitution e = (v2-v1)/(u1-u2) let impulse provided till destitution or deformation be J1 and impulse provided for restitution be J2. then, J1/(J1+J2) = 1/(1+e). Having calculated J1, find the base of the triangle with area = J1 and height(obviously) as 150 units
```
2 years ago
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### Course Features

• 731 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions