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Grade: 12

                        

Dividing a repeating 6-digit number by 7, then by 13 Select a 3-digit number. Repeat these digits to make a 6-digit number. Divide these 6 digits by 7, then by 13. The answer is 11 times the first three digits! Example: If the 3-digit number selected is 234: The 6-digit number is 234234. Divide by 7, then by 13: multiply by 11 - to multiply 234 by 11, work right to left: last digit on right = _ _ _ 4 next digit to left = 3 + 4 = 7: _ _ 7 _ next digit to left = 2 + 3 = 5: _ 5 _ _ last digit on left = 2 _ _ _ So 234234 divided by 7, then 13 is 2574. See the pattern? If the 3-digit number selected is 461: The 6-digit number is 461461. Divide by 7, then by 13: multiply by 11 - to multiply 461 by 11, work right to left: last digit on right = _ _ _ 1 next digit to left = 6 + 1 = 7: _ _ 7 _ next digit to left = 4 + 6 = 10: _ 0 _ _ last digit on left = 4 + 1(carry) = 5: 5 _ _ _ So 461461 divided by 7, then 13 is 5071.

6 years ago

Answers : (1)

Sourabh Singh
IIT Patna
askIITians Faculty
2104 Points
							Hii

Thanks for the info but I was expecting a question .Ask your question and we will help you out.
4 years ago
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