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Grade: Upto college level

                        

consider the number 4523895099854 triplet pairs are 4...523...895...099...854 alternate sums are 4+895+854=1753 and 523+099=622 difference = 1131 revise the same tripling process 1......131 so difference = 131-1 = 130 divide it by 7 we get reminder as 4 divide it by 11 we get reminder as 9 divide it by 13 we get reminder as 0

6 years ago

Answers : (1)

Sourabh Singh
IIT Patna
askIITians Faculty
2104 Points
							hii

the question is not proper. Resubmit the question properly and we will get back to you.

Thanks. . . . . . .






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5 years ago
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